Fluid Flow & Aerodynamics
why things fly, and why the usual explanation is wrong
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The thread: What is conserved — page 45

Page 45 of 48, continuing through the 424 essays this motif runs through.

424 essays carry this thread — page 45 of 48.

Behind the lip the ceiling is set by starting, not by the cowl. The best total-pressure recovery with every compression isentropic but the terminal normal shock, against free-stream Mach number: an external ramp turning to the free stream's detachment angle; the same ramp followed by the largest internal contraction a fixed duct can start through, Kantrowitz's limit; and the same ramp followed by a contraction to a throat Mach number of 1.2, which only a duct that opened its throat to start can hold. At Mach 3 the three are 88.5%, 95.1% and 99.3%; at Mach 4, 71%, 82.5% and 99.3%. Compressible flow

Compression behind the lip is bought by opening the throat

The cowl caps how far an intake's ramps can turn the flow, and moving some of the compression inside the duct escapes the cap. It does not escape the duct's other limit: a duct that contracts a supersonic stream has to swallow the shock that stands at its lip while it starts. With fixed walls that allows a contraction of about a tenth, and at Mach 3 six shocks with three inside recover exactly what six outside do. A duct that opens its throat to start and closes it after recovers 94 per cent — the internal compression is paid for by the moving wall, not by the walls being inside.

 Small scales forget fast and large ones slowly, and the window only sees the large. Each scale's memory over a single probe's integral time against wavenumber in inverse samples, for one memory at every scale and for memories falling as the wavenumber to the minus two-thirds and minus one above the field's own wavenumber, 1/λ, and held there below it. All three give the same probe integral time; the window of 64 samples passes wavenumbers below about 2π/64 = 0.098, where the sweeping law's memory is 1.26 probe times and the single law's 1. Transition and turbulence

The camera needs the window's memory, not the probe's

A run of particle-image frames stops gaining independent values for its mean once frames are closer than the flow's memory — but the memory that counts is the window mean's, and when large eddies live longer than small ones it is longer than the integral time a single probe measures. Give each scale its own memory and the frame rate that stops buying moves by up to a quarter where the flow forgets before it is swept, by nothing where the sweep sets it, and by however much longer the largest eddies live. Fed the window's own memory, the single-memory rule gives it back to two per cent.

 Hold the nozzle further from the plate and the jet arrives slower but leaves a stronger wall jet. For a laminar jet from a 2 mm slot at 5 cm/s in water, against the nozzle's distance from the plate, each over its value at 10 cm: the arriving centreline speed, which falls as h^−⅓; the inherited invariant F = 3KQ/32, which grows as h^⅓ because the jet has gathered fluid; and the wall jet's peak speed a metre along the plate, which grows as h^⅙. At 2 cm the arriving speed is 1.71 of its value at 10 cm and the far wall jet 0.765; at 2 m, 0.368 and 1.65. Viscosity

A jet striking a plate leaves a stronger wall jet the further it travelled

A plane jet that strikes a wall splits into two wall jets, and each keeps not the jet's momentum but Glauert's flux of momentum flux. Turned without loss at the stagnation point, each half arrives laid along the wall with its axis on the wall, and its invariant is the momentum it brought times the fluid it had gathered on the way: F = 3KQ/32. Hold the nozzle further away and the jet arrives slower but leaves a stronger wall jet, by the cube root of the distance — and the wall jet takes a distance of about the Reynolds number in jet widths to forget it was ever free.

 At the equator the front runs as long as the land is warmer; at forty-five degrees it stops hours before. The sea-breeze front's distance inland against the hours since the land first became warmer than the sea, at the equator and at 30°, 45° and 60°. At 0° it reaches 185 km. At 30° it reaches 133 km, 99 per cent of that by hour 11. At 45° it reaches 99.2 km, 99 per cent of that by hour 9.1. At 60° it reaches 80.3 km, 99 per cent of that by hour 8. The quasi-steady estimate, the head speed of a current fed from a deep reservoir at each hour's contrast, integrated, is 189 km. Ideal flow

The sea-breeze front runs till evening only near the equator

A real sea breeze arrives: the cool sea air runs inland under the warm air as a gravity current, its head moving at a speed set by the density contrast and the depth of the cool layer. How far it gets depends on the latitude. Near the equator the head keeps running as long as the land stays warmer, and the length of the afternoon decides the reach. In mid-latitudes the Earth's rotation turns the current along the coast and stops the head hours before the contrast ends, a third further inland than the Rossby radius, and a longer afternoon adds nothing.

 A root's bending moment weighs the gust by the loading of a wing twisted like its moment arm. Across the span of an elliptic wing of aspect ratio 9, each normalised to unit area: the lift's weight, the loading at uniform incidence; the two roots' bending moment's, the loading of a wing washed in as |y|, with a hole at the root; and the right root's alone, the loading of a wing washed in as y on the right half and not at all on the left. The one-root weight reaches across to the left wing through the induced flow, and it is not symmetric. Circulation and lift

One wing root feels the rolling gust its lift cannot

The reverse-flow theorem says the gust weight of any load is the loading the wing would carry at an incidence shaped like that load's arm. For the lift that is the familiar uniform-incidence loading. For the bending moment at one root it is the loading of a wing washed in towards one tip only — a weight that is not symmetric, and so passes the rolling half of a gust that the lift and the two roots together cancel. That half is a sliver of the variance and adds up to a fifth to how often the root's moment crosses its mean.

 Of the four common plumes, only the laminar one above a line speeds up as it rises. Centreline speed against height for four plumes, each scaled to its own speed at one reference height: laminar above a line source, rising as the fifth root of height; laminar above a point source and turbulent above a line, both constant; and turbulent above a point, falling as height to the minus one third. Each exponent follows from the heat flux being fixed and the width growing by diffusion, √(νx/u), when laminar, or in proportion to height when turbulent. Regimes and numbers

Above a warm wire the plume speeds up as it rises

A plume above a line of heat has no wall, no imposed speed and one conserved quantity, the heat it carries. That alone fixes a centreline speed growing as the fifth root of height — the only one of the four common plumes that accelerates — a temperature excess falling as the three-fifths power, and a warm core that is narrower than the moving sheet around it in any fluid more viscous than five ninths of its own diffusivity. At that Prandtl number the equations have a closed form, and the solver lands on it to three parts in a million.

 A cone swallows its sheath as the cube root of the Reynolds number; a cylinder in proportion to it. The swallowing distance in nose radii against the Reynolds number on the nose radius at Mach 15: a 7° sphere-cone, laminar and turbulent, and the sphere-cylinder of the same nose, laminar. At Reₙ = 10⁵ the cone's laminar layer swallows the sheath at 160 nose radii and its turbulent one at 28.1; the cylinder's laminar layer at 1.36·10⁵. Compressible flow

A blunted cone eats its nose's sheath in a few hundred radii

A sphere-cylinder's boundary layer takes a third of a Reynolds number of diameters to get through the hot sheath its nose leaves, which on any real body is never. Put the same nose on a slender cone and the answer collapses: the cone's widening perimeter feeds the boundary layer so fast that it swallows the sheath in tens to hundreds of nose radii, growing only as the cube root of the Reynolds number. On a two-metre cone at Mach 15 that makes a nose of about two centimetres the line between a base still bathed in the nose's gas and one that has forgotten it.

 The washout a mission wants rises with the lift coefficient; a twist driven by dynamic pressure rises the other way. Washout against lift coefficient for the trainer's sortie: each lift coefficient's own best washout, 7.87° per unit of it; the best fixed washout, 3.43°; the best twist that varies with dynamic pressure, which has to wash in as the aeroplane speeds up; and a twist of the natural sign, one degree of extra washout at cruise growing with dynamic pressure, from a nose-down pitching moment. The four segments sit at Cₗ 0.82, 0.33, 1.3, 0.92. Circulation and lift

A wing that twists with its speed washes out the wrong way

A fixed washout is right at one lift coefficient, and a flight that spends its time at four of them pays for the spread. A wing whose twist changed in flight could follow — but the twist a real wing gets for free is driven by dynamic pressure, and it adds washout as the aeroplane speeds up, exactly where less is wanted. On a trainer's sortie a degree of it at cruise raises the induced energy by a third of a point. The best twist driven by dynamic pressure washes in, and only one that follows the incidence itself removes the spread entirely.

 At the cheapest fork each daughter runs at the parent's velocity along it, so the split loses only the sideways part. The power lost at a symmetric split, as a multiple of the flow times the parent's dynamic pressure, against the daughters' radius as a fraction of the parent's, at each of three cheapest angles. For laminar, k = 3 the angle is 37.5°, the curve's minimum is at a ratio of 0.7937 — the cheapest ratio — and its value is sin²θ = 0.37; for smooth turbulent, 27/11 the angle is 28.4°, the curve's minimum is at a ratio of 0.754 — the cheapest ratio — and its value is sin²θ = 0.226; for rough, 7/3 the angle is 25.1°, the curve's minimum is at a ratio of 0.743 — the cheapest ratio — and its value is sin²θ = 0.18. Fluids at work

The cheapest fork loses only its sideways speed, and pricing it closes the fork

A turbulent network built at least cost forks at 28.4°, with daughters three quarters of the parent's radius, and those numbers priced the pipes and never the split. Price the split as Borda priced a sudden widening and something exact appears: at the cheapest fork each daughter already runs at the parent's velocity component along it, so the junction loses nothing but the sideways part of the parent's speed, and its loss cannot be reduced by resizing the daughters. It can be reduced by narrowing the fork. A split costing under two per cent of the bill moves the cheapest angle by seven degrees, because the pipes' bill is flat at its best angle and the split's loss is not.

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