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The thread: The exact theory is wrong — page 26

Page 26 of 31, continuing through the 276 essays this motif runs through.

276 essays carry this thread — page 26 of 31.

A film pulled apart asks for more tension than a liquid has. The pressure below ambient in the film under a sphere moving away from a wall, scaled by the tension the liquid can bear, against the distance from the axis in sphere radii, at the contact gap. The lubrication solution (dashed) asks for four times that tension on the axis. A liquid that cannot give it cavitates: a disc of vapour opens where the demand exceeds the floor, and outside it the pressure is exactly the solution it would have had. Here the disc reaches 0.12 sphere radii. Viscosity

A torn film still pulls

A sphere bouncing off a wall under liquid has to climb back out through the film it squeezed, and the film pulls it back with a suction no real liquid can supply. Let the liquid cavitate and the obvious guess is that the sphere escapes the torn part of the film for free. It does not. The liquid round the vapour disc goes on pulling, and the disc itself holds the full tension over its area, so a film that tears at five times the contact gap saves a third of what the guess says — and the rebound threshold moves by five per cent where the guess said a third. At an atmosphere, in the liquids the threshold was measured in, it barely moves at all.

A hydrofoil loses lift at speed and gains it slowly, with a dip between. The lift of a flat hydrofoil beneath the surface over its value in deep water, against the chord Froude number U/√(gc) on a logarithmic axis, at depths of half a chord, one chord and two. Slow, the surface is a lid and the foil gains lift, as a wing over the ground does. Fast, the surface is a pressure-release boundary and the foil loses it. Between the two it does not simply pass from one to the other: the lift dips well below its fast value where the foil's waves are longest compared with its depth, and then rises through the lid value before settling back on it. What is taught wrongly

A hydrofoil loses most lift on the way up

A wing near the ground gains lift, and a hydrofoil near the surface is often described as the same thing upside down. At low speed it is: the surface acts as a lid and the foil gains lift. At high speed the surface is a boundary that cannot hold a pressure, and the foil loses lift instead. But the lift does not pass smoothly from one to the other. Between them, where the foil's waves are a few depths long, it falls well below both — to 43 per cent of its deep-water value half a chord down — and a foil boat meets that speed in the middle of its take-off run.

A bow shock that grows as a line explosion does. The radius of the bow shock around a hemisphere-nosed cylinder, in body diameters, against distance behind the nose: the blast-wave analogy, R/d = 0.795 C^¼ (x/d)^½ with C, the drag coefficient, 0.919, which contains no Mach number, and Billig's correlation of measured bow shocks on spheres at Mach 5, 10 and 20, anchored at the nose and continued as a hyperbola to the Mach cone. Both grow as the square root of the distance; at Mach 20 the analogy's shock is a steady 0.71 of Billig's. Compressible flow

A hypersonic body leaves a line explosion behind it

A blunt body at hypersonic speed does work on the air at a rate equal to its drag, and each slice of air it passes through is struck once and left to expand. Seen from the ground, that is a line explosion, and Sedov's cylindrical blast wave gives the bow shock's width and the pressure on the afterbody without a Mach number in either. The analogy's classical constants come straight out of the blast solution. So do its limits: it holds only while its own shock stays strong, over a length that grows as the square of the flight Mach number, and it puts the body inside a core hotter than anything the flow can reach.

Released, the side-by-side pair collides and the tandem pair parts. The distance between the centres of two cylinders released from rest in an ideal stream and free to move along the line joining them, against time in radii over the stream speed. Side by side they are drawn together and collide — neutrally buoyant ones released four radii apart after 6.5, bubbles, with no mass of their own, after 4.82. In tandem they are pushed apart and keep going. Ideal flow

A pair set free in a stream collides or parts

Two cylinders held in an ideal stream pull together side by side and push apart in tandem. Let them go and the forces become a motion, and the motion has a law of its own: the stream's force on each is exactly the slope of how large the pair looks from far away, so the pair moves to look bigger. Side by side that means closing, and the fluid squeezed out of the gap costs so little that nothing stops them: released four radii apart they collide in six and a half radii of stream. In tandem it means parting, for good.

Remembered pressure turns the runaway into a teardrop. The velocity gradient's two invariants, Q against R, both scaled by the mean enstrophy, for an ensemble of parcels whose pressure remembers one Kolmogorov time of deformation, at a memory of a tenth of a large-eddy time. The restricted Euler equation sends every parcel off to infinity along the right-hand branch of Vieillefosse's curve, dashed. With the remembered pressure the parcels stay: they crowd along that branch in the strain-dominated quadrant and above the axis on the left where vortices are being stretched — the teardrop measured in turbulence. Flows and fields

The pressure a parcel remembers keeps it finite

The restricted Euler equation follows a parcel's velocity gradient with the pressure's shape thrown away, and every gradient it follows blows up. Give the parcel back a pressure that remembers how its neighbourhood was deformed over the last Kolmogorov time — nothing more — and no gradient blows up at all. The ensemble settles into the teardrop measured in turbulence, its vorticity lines up with the middle strain axis, and its intermittency grows as the memory shortens. What the memory cannot do is keep the one identity homogeneity demands, and that miss says where the rest of the pressure lives.

Every rotor lands on the same hot state, later and more smoothly. The centre temperature against time, on a logarithmic axis, for a soft drive five per cent past its fold switched on from rest, with rotors of four inertias. Each climbs, lingers and jumps, and each ends at the hot operating point without overshooting it. The time to pass three e-folds is 7, 16, 101, 948 diffusion times for M = 0, 0.1, 1, 10. Viscosity

A rotor's inertia slows the jump and cannot make it ring

Give the motor driving a self-heating oil film a rotor that has to spin up, and there are two clocks: the film's diffusion time and the rotor's. Two clocks are what an oscillator is usually made of, and this pair cannot make one. Every eigenvalue stays real at every inertia, because the film and the rotor only ever push each other the same way. What inertia does instead is add its own delay to the film's, and in a real machine, where the rotor is hundreds of times slower, the delay past the fold is almost entirely the rotor's.

Joined at the tips, the spars share the moment as a couple. The share of the lift's root bending moment that the box wing's two spars carry as an axial couple — one in tension, the other in compression, the gap for a lever arm — against the fins' bending stiffness as a multiple of a spar's, for gaps of a tenth, a fifth and two-fifths of the span. With floppy fins the spars bend independently and the couple is nothing. With fins as stiff as the spars, which a fin of the wing's own section is, the couple carries 29 per cent at a gap of a fifth. However stiff the fins, it stops near a third. Circulation and lift

A box wing's fins earn their keep in the spar

Constrain a box wing's root bending moment and its fins stop saving drag: it becomes a biplane. But that constraint counted the lift's moment, not the spars', and the fins join the spars into one frame. Joined at the tips, the two spars hand part of the moment to a couple across the gap — tension in one, compression in the other — which costs far less material than bending. With fins as stiff as the spars that is three-tenths of the moment; with rigid fins it stops at a third, whatever the gap, because a tip joint can only guide a tip. Counted in the spar, the box has less drag and a lighter spar than the elliptic monoplane at once.

A quiet flame has one cusp; a noisy one keeps making more. Two flame fronts twenty neutral wavelengths wide, burning upwards, drawn apart for clarity: above, the quiet front, the exact pole solution with one cusp per period and the most poles it can hold; below, the same flame with a noise of a millionth kicking its growing wavelengths. The noise keeps seeding small wrinkles on the smooth arcs; each grows as it is swept along the arc into the cusp, so the noisy front carries a train of sub-cusps the quiet one never has, and advances at 0.862 against the quiet 0.5. Flows and fields

A flame's speed limit holds only in silence

A quiet wrinkled flame settles into a single cusp and a speed it never exceeds, however wide it grows. Add noise and the limit is gone. A disturbance of one part in a million million already speeds the front up; one in a million makes it a third faster; and a noisy flame, unlike a quiet one, keeps getting faster as it gets wider, because every added width is room for more wrinkles to be born on its arcs and swept into its cusp. The quiet flame's speed is a property of a silence no burner has.

The largest nucleus decides how tall a siphon can be. The tallest crown a siphon of degassed water can run over, above the upper reservoir's surface, against the radius of the largest gas nucleus the water carries, for outlets 0.2, 1 and 3 m below the upper reservoir. Nuclei of ten microns and more leave the ordinary limit of about ten metres, where the crown reaches the vapour pressure. A largest nucleus of one micron lets a slow siphon stand 14.4 m tall; of three-tenths of a micron, 27.3 m. The water's own strength is never the limit: its dirt is. What is taught wrongly

A degassed siphon is as tall as its largest nucleus allows

The textbook says a siphon cannot lift water more than about ten metres, because above that the pressure at its crown would fall below zero. Water can hold a pressure below zero — a tension — and siphons of degassed water have run over crowns taller than the barometric height. How much taller is not set by the water's strength, which is enormous, but by the largest speck of gas it carries. A nucleus of a micron lets a slow siphon stand fourteen metres tall; three-tenths of a micron, twenty-seven. And the flow's own speed takes metres off every limit.

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